Ira S. answered 08/09/14
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I'm sure you know the quadratic formula so the numerator determines the sign of the entire fraction since it has the + or - . So we want to insure that -b + sqrt b^2-4ac and -b - sqrt b^2-4ac have opposite signs. Let's take some real examples so we can get a handle on the problem before generalizing.
4 + 7 and 4-7 comes out to 11 and -3 opposite signs so good
4 +1 and 4-1 comes out to 5 and 3 same sign so bad
-5 + 3 and -5 - 3 comes out to -2 and -8 same sign so bad
-5 +9 and -5 -9 comes out to 4 and -14 opposit signs so good
What's so special about case 1 and case 4? The second number is bigger than the first? Be careful before you make generaliziations!!! Case 3 also has this property...3 is bigger than -5 but 3 is not bigger than | 5 | ...... the absolute value of 5. So the second number must always be bigger than the absolute value of the first. So,
sqrt b^2-4ac must be greater than the absolute value of -b. That is b^2-4ac > |-b|.
The only other condition that must hold is that b^2-4ac must be positive otherwise you get equal roots or complex roots.