Jesse S. answered 12/09/17
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Amount of 10% fat-content chocolate=x
amount of 50% fat-content chocolate =y
x + y =200 ____________ eq 1
so x =200 -y
10 % of x + 50 % of y = 12 % of (x +y)
0.1 x + 0.5 y = 0.12(x+y)
0.1 x+0.5y =0.12x +0.12y
0.02x - 0.38 y =0 ____________ eq 2
substitute x = 200 -y in eq 2
0.02(200-y) -0.38y =0
4 -0.02 y -0.38y =0
4 -0.4y=0
0.4 y = 4
y =4/0.4 = 10
x =200 -10 =190
Amount of 10% fat-content chocolate=x =190 kg
amount of 50% fat-content chocolate =y = 10 kg
amount of 50% fat-content chocolate =y = 10 kg