
Arturo O. answered 12/09/17
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Normal force:
N = mg cosθ
Smooth surface:
d = a1t12/2 = g sinθ (t/2)2/2 = g sinθ t2/8
Rough surface:
d = a2t22/2 = (g sinθ - μN/m) t2/2 = (g sinθ - μg cosθ) t2/2
d = g(sinθ - μcosθ)t2/2
It is the same d for both the smooth and rough surfaces, so
g(sinθ - μcosθ)t2/2 = g sinθ t2/8
sinθ - μcosθ = sinθ /4
μ = (3/4)sinθ / cosθ = (3/4)tanθ = 0.75 tan45º = 0.75
μ = 0.75 [coefficient of kinetic friction]