J.R. S. answered 12/06/17
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Molarity = moles solute/liter solution
Molality = moles solute/kg solvent
Let's first find moles of solute:
2.27 g Na2CO3 x 1 moles/106 g = 0.0214 moles solute
Next, we can find the mass of solvent:
251.60 g solution - 2.27 g solute = 249.33 g of solvent = 0.24933 kg solvent
The volume of solution is given as 250 ml = 0.250 liters.
So,
MOLARITY = moles solute/liter solution = 0.0214 moles/0.250 liters = 0.0856 M (3 significant figures)
MOLALITY = moles solute/kg solvent = 0.0214 moles/0.24933 kg = 0.0858 m (3 significant figures)