hello i need help to solve 4^x=3^x+1 i can't find out how to do it i know that i have to use LOG but how??? could you help me step by step?? Jakob
4^x=3^(x+1) <==Is this what you want to solve?
xln4 = (x+1)ln3, using the log property lna^b = blna
Solve for x,
x = ln3/(ln4 - ln3) <==Answer