
Arturo O. answered 11/30/17
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Assuming a coefficient of kinetic friction μk, mass m of the object, and a constant opposing force of friction,
f = -μkmg
v(t) = v + at
a = f/m = -μkmg/m = -μkg
Set v(t) = 0 and solve for t.
0 = v + at = v - μkgt
t = v/(μkg)
Distance to stop:
vf2 - vi2 = 2ad
02 - v2 = -2μkgd
d = v2/(2μkg)