calculate the volume of 0.750 mol/L sulfuric acid needed to neutralize completely 20 g if sodium hydroxide

Question

How would you calculate the volume with the given information

Answer 1

First, write the correct balanced equation for the reaction:

2NaOH + H₂SO₄ ==> Na₂SO₄ + 2H₂O

Next, determine moles of NaOH present:

20 g NaOH x 1 mole NaOH/40 g = 0.5 moles NaOH

Next, determine number of moles H₂SO₄ needed to react with 0.5 moles NaOH(see balanced eq.):

0.5 moles NaOH x 1 mole H₂SO₄/2 moles NaOH = 0.25 moles H₂SO₄ needed

Finally, calculate the volume of H₂SO₄ needed to provide 0.25 moles H₂SO₄:

(0.750 mole/L)(x L) = 0.25 moles and x = 0.333 L = 333 ml