Sasha C.
asked • 11/27/17sin(A-B) over sinA-SinB equals cotB-cotA
establish an identity
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1 Expert Answer
The identity should be sin(A-B)/(sinA sinB)=cotB-cotA and this is because the left hand side of the equality is the same as sin(A-B)/ (sinA sinB)=(sinA cosB- cosA sinB)/(sinA sinB)=cosB/sinB - cosA/sinA = cotB - cotA which finishes the claim.
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Lois C.
I'd like to help you, but I need you to clarify if the denominator under sin(A - B) is the entire subtraction expression of Sin A - Sin B or if it is just the Sin A part and then the Sin B is subtracted after the division.04/03/20