
Don J.
asked 11/22/17Choose the value of k that makes the following function continuous at x=1: help!?
f(x) =
1. -8x^2+48x-40/(x-1) x is less than 1
2. -2x+k x is greater than or equal to 1
More
1 Expert Answer
Michael J. answered 11/22/17
Tutor
5
(5)
Mastery of Limits, Derivatives, and Integration Techniques
The function is continuous if the functions intersect at 1. First, we need to factor the first part.
(-8x2 + 48x - 40) / (x - 1) =
-(8x2 - 48x + 40) / (x - 1) =
-8(x2 - 6x + 5) / (x - 1) =
-8(x - 1)(x - 5) / (x - 1) =
-8x + 40
Now we set this equal to (-2x + k) at x=1.
-8(1) + 40 = -2(1) + k
Solve for k. I live this part up to you.
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Andrew M.
Remember that dividing by zero is undefined.. We cannot divide by zero,
which means a function cannot have zero in the denominator.
There is no "k" in your first expression:
-8x^2+48x-40/(x-1) x is less than 1
but this is not continuous at x=1 because that would make the denominator zero.
2. -2x+k x is greater than or equal to 1
This is continuous for any real value of k
11/22/17