If 3(y + 13) = 30, find the value of 1/6y

Question

If 3(y + 13) = 30, find the value of
1/6y

Answer 1

3(y + 13) =30

y+13 = 10

y = -3

 

Can you finish from here?

Answer 2

3(y + 13) = 30

 

y+13 = 10  <--- divides both sides by 3

 

y = 10 - 13 = -3  <--- subtracts 13 from both sides

 

1/6*y = (1/6)(-3) = -3/6 = -1/2

Answer 3

3(y + 13) = 30

3y +39 =30

 

3y =-9

 

multiply both side with 2

 

6y =-18

 

so

1/6y = -1/18