Hello Tony,
First, let's take stock of our given info:
Δx=-60m (negative because it moves down)
v0=7m/s (positive because it is up)
a=-9.81m/s2 (negative because it accelerates down.I assume this is the you are using for gravity. If you are rounding differently, use that value instead.)
t=?
We want to choose a formula that only has only one unknown value so we can solve for it. Let's use:
Δx=v0t+1/2at2
And plug in our values.
-60=7t+1/2(-9.81)t2
-60=7t-4.905t2
This looks like a quadratic, so lets set equal to 0
-4.905t2 +7t+60=0
Now we can solve using the quadratic formula:
t=(-b±√(b2-4ac))/2a
a=-4.905
b=7
c=60
Plug in the values:
t=(-7±√(72-4(-4.905)(60)))/(2*-4.905)
=(-7±35.017)/14
t = -3.00s or t=2.00s
We have to throw out the negative answer since it doesn't make sense in asking how long it took for the ball to fall. So our answer is 3 s.