a 7.35 L container holds a mixture of two gases at 55 degrees C. the particles of gas A and gas B, respectively, are 0.248 atm and 0.531 atm. *continued below

Question

* if 0.150 mol of a third gas is added with no change in volume or temp, what will the total pressure become?

Answer 1

Pressure of 3rd gas is found from PV=nRT. P=nRT/V

P=(0.15)(0.0821)(328)/7.35

 

After solving for the pressure contributed by the third gas, add it to 0.248 atm + 0.531 atm to get total pressure.