J.R. S. answered 11/06/17
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......H2(g) + I2(g) ====> 2HI(g)....
I....3.10...........2.2...............0.........
C..-2.17.......-2.17............+2x2.17....
E...0.93........0.030...........4.17.........
Kc = [HI]2/[H2][I2]
Kc = (4.17)2/(0.93)(0.03)
Kc = 623