
Kenneth S. answered 11/02/17
Tutor
4.8
(62)
Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
There is only one distinct subset for the 7 specific people. But the other two chosen to be in the top 9 can be anybodies,
Therefore P(E) = 1•5C2 / 12C9
I leave the actual computation to you. Do you agree?