I have found mols of HCl and I have found mols of the unknown Metal (M). What are my next steps?
I have found the mols of the HCl solution and I have found the mols of the unknown M. I divided by the mass to get 53.89g/mol. What I did next was find the mols of NaOH by using the formula M=mols/L. What I calculated was 0.00224mols of NaOH. I then took my 53.89g/mol and divided that by the 0.00224mols of NaOH. From that I got a ridiculous number that does not even come close to the numbers on the periodic table. Where did I go wrong in my steps?
Balanced chemical equation: 2M(s) + 6HCl(aq) ==> 2MCl3 + 3H2(g)
Question: 0.0900 g of metal is reacted with 50.00 mL of 0.100 M HCl. Once the reaction is complete, the reaction mixture is titrated with 0.1375 M NaOH. It requires 16.35 mL of NaOH to reach the endpoint. What is the molecular weight of the metal that was reacted?