A rectangle has a length six inches less than twice the width. If the perimeter of the rectangle is 84 inches, find the dimensions.

Question

Perimeter=2L+2W

Answer 1

width = W

length = L= 2W-6

 

P = 2L+2W

84=2(2W-6) + 2W

84= 4W -12 + 2W

84 = 6W -12

84+12 = 6W

96 = 6W

W=16

 

Solution

W=16

L = 2(16)-6 = 32-6 = 26

 

Answer 2

w = width

l=2w-6

2l + 2w=84

2(2w-6) + 2w = 84

6w-12=84

6w=96

w=16

l=2(16)-6 =32-6=26

width is 16, length is 26