y=1/3x−1 parallel to (6,3)

Question

Please help with this math problem. Thank you :)

Answer 1

What you meant is to find the equation of the line that is parallel to y = (1/3)X - 1 and passes through (6,3).

The slope of the given line is 1/3

 

Parallel lines have the same slope, so the parallel line has slope 1/3.

It passes through (6,3), so x=6 and y=3 with slope M=1/3

 

Equation of the line: y = mx + b

                              3 = (1/3)(6) + b

                              3 = 2 + b

                              b = 1

 

y = (1/3)X + 1