A newspaper carrier has ​$7.25 in change. He has ten more quarters than dimes but four times as many nickels as quarters. How many coins of each type

Question

A newspaper carrier has $7.25 in change. He has tenten more quarters than dimes but four times as many nickels as quarters. How many coins of each type does he have?

Answer 1

25Q + 10D + 5N = 725 <--- amount in pennies to clear away the decimals

 

Q = D + 10 ---> D = Q - 10

 

N = 4Q

 

25Q + 10(Q - 10) + 5(4Q) = 725

 

25Q + 10Q - 100 + 20Q = 725

 

55Q - 100 = 725

 

55Q = 825

 

Q = 825 / 55 = 15

 

15 quarters

60 nickels

5 dimes