A line that's perpendicular to x-6y=2 and passes through (2,4)

Question

This is about math homework 

Answer 1

Find a line perpendicular to x-6y=2 and passes through (2,4).

First: find the slope of the original line.  rearrange to x-2=6y; divide by 6 so ( 1/6)x - 1/3 = y so m = 1/6.

Second: find the negative inverse of 1/6 to get the perpendicular...the answer is -6.

Third:  Plug into Y-4 = -6(x-2) and solve.

                         y-4 = -6x +12

Finally:               y=-6x+16

 

(plug x = 2 into equation to verify.  y=(-6)(2) + 16 = 4