Sorry this is my question it was incomplete

Question

A chemical antifreeze company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The premiun solution contains 95% pure antifreeze. The company wants to obtain 190 gallons of a mixture that contains 40% pure antifreeze. How many gallons of water and how many gallons of the premium antifreeze solution must be mixed?

Answer 1

(x gal)(95%) + (190 gal - x gal)(0%) = (190 gal)(40%)

95x + 0 = 7600

x = 80 gallons of premium 95% + 110 gallons of water.