Finding Final Temperature Chemistry

Question

A 41 kg sample of water absorbs 374 kJ of heat. If the water was initially at 25.1 ∘C, what is its final temperature?

Answer 1

q = mCΔT

374 kj = (41kg)(4.184kj/kg/deg)(ΔT)

ΔT = 374 kj/(41 kg)(4.184 kj/kg/deg)

ΔT = 2.2 degrees

Final temp = 25.1 + 2.2 = 27.3 degrees