
Arturo O. answered 10/01/17
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(1)
From the initial position of car 2, car 1 travels a distance
d = vt,
and car 2 travels the same distance distance, but given by
d = (1/2)at2
v = 20 m/s
a = 2 m/s2
(1/2)at2 = vt
t = 2v/a = 2(20)/2 s = 20 s
(b)
To answer this question, we need to know how far apart the cars were at the beginning.