One integer is twice another. their sum is 96. find the numbers

Question

I am lost entirely with the integers part of the question

Answer 1

let the two integers be n and 2n, i.e. "One integer is twice another."

n + 2n = 96 is their sum. NOW can you solve for n??

Answer 2

The smaller integer is X.

Twice as big means 2X.

Their sum is 96, so

 

X + 2X = 96

 

3x = 96

 

x = 32

 

They are 32 and 64