Andrew M. answered • 09/21/17
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Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
9s3 - 2s2 + 81s - 18 =
9s3 + 81s - 2s2 - 18 =
9s(s2 + 9) -2(s2 + 9) =
(9s - 2)(s2 + 9)
Rick S.
asked • 09/21/17Factor by grouping. 9s^3 − 2s^2 + 81s − 18
Factor by grouping.
9s3 − 2s2 + 81s − 18
9s3 − 2s2 + 81s − 18
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2 Answers By Expert Tutors
Arturo O. answered • 09/21/17
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Experienced Physics Teacher for Physics Tutoring
Factor the first 2 terms into a product, factor the second 2 terms into a product, then factor the sum.
9s3 - 2s2 + 81s - 18 = s2(9s - 2) + 9(9s - 2) = (s2 + 9)(9s - 2)
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