if the point (2k-3,k+2) lies on the graph of the equation 2x+3y+15=0,find the value of k

Question

if the point (2k-3,k+2) lies on the graph of the equation 2x+3y+15=0,find the value of k

 

Answer 1

Since the point lies on the graph, it must satisfy the equation.

 

So, 2(2k-3) + 3(k+2)  + 15 = 0

 

      4k - 6 + 3k + 6 + 15 = 0

 

                                 7k = -15

 

                                   k = -15/7