Use exact arithmetic to solve the following system: 10^{-3}x-y=1, x+y=0. The book says the answer is (1/1.001, -1/1.001). Please show all your work step by step. Thanks. Jul 20 | Sun from Los Angeles, CA | 1 Answer | 0 Votes Mark favorite Subscribe Comment
(0.001)x-y = 1 [10^{-3} = 0.001] x+y=0; Therefore y = -x Plugging y = -x into the first equation: (0.001)x -(-x) = 1 1.001x = 1 x = 1/1.001 y = -x = -1/1.001 Jul 20 | Philip P. Comment