Three consecutive integers with a sum of -36

Question

Show me work and equation like solve it 

Answer 1

x+(x+1)+(x+2)=-36

3x+3=-36

3x=-3-36

3x=-39

x=-39/3

x=-13

x+1=-12

x+2=-11

-13, -12, -11 are the numbers

without algebra...

-36/3=-12, which is the middle number

-13 and -11 are the other numbers