Next two terms in sequence 64,32,16

Question

I have home work but I don't understand it and nobody can help me

Answer 1

This is a geometric sequence where r = 1/2

To find the a_n term of a geometric sequence, we can use the following formula:

 

a_n = a₁ * r^{n - 1}

 

a₁ = the first term in the sequence, which is 64

 

The next two terms in this sequence would be a₄ and a₅

 

a₄ = 64 * (1/2)^{4 - 1} = 64(1/2)³ = 64(1/8) = 64/8 = 8

 

a₅ = 64 * (1/2)^{5 - 1} = 64(1/2)⁴ = 64(1/16) = 64/16 = 4

Answer 2

64 / 2 = 32

32 / 2 = 16

16 / 2 =

 

Can you do it?