
Andrew M. answered 09/04/17
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
Arturo is correct; however, given the way your problem
is stated, I assume your instructor expects you to set up
your 3 odd integers as 2n+1, 2n+3, 2n+5:
2n+1 + 2n+3 + 2n+5 = 63
6n + 9 = 63
6n = 54
n = 9
1st integer = 2n+1 = 19
2nd integer = 2n+3 = 21
3rd integer = 2n+5 = 23