sinΘ+sin

^{2}Θ=1 then cos^{2}Θ+ cos^{4}Θ=?sinΘ+sin^{2}Θ=1 then cos^{2}Θ+ cos^{4}Θ=?

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Saugus, MA

sin(x)+sin^{2}(x)=1

sin^{2}(x)+cos^{2}(x)=1 is a trig identity

sin(x)+sin^{2}(x)=sin^{2}(x)+cos^{2}(x)

sin(x)=cos^{2}(x)

Looking at cos^{2}(x)+cos^{4}(x) we have:

sin(x)+[cos^{2}(x)]^{2}

sin(x)+[sin(x)]^{2}

sin(x)+sin^{2}(x) which equals 1 from your hypothesis above

Therefore cos^{2}(x)+cos^{4}(x)=1 also

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