what is the third number in the sequence?

Question

the sum of 5 consecutive integers is 120.

Answer 1

Let n be the 3rd number.  Then

 

(n - 2) + (n - 1) + n + (n + 1) + (n + 2) = 120

 

5n + (-2 -1 + 0 + 1 + 2) = 120

 

5n = 120

 

n = 120/5 = 24

 

You could also say that n is the average of 5 numbers that add up to 120, so

 

n = 120/5 = 24