Kenneth S. answered • 08/12/17
Tutor
4.8
(62)
Calculus will seem easy if you have the right tutor!
If the horizontal leg of the rt triangle is x and the vertical leg is y (instead of h), then you have tan θ = y/x or y=xtan θ.
Differentiating implicitly gives dy/dt = (dx/dt)tan θ + x (dθ/dt)sec2θ
Unfortunately, I believe that this question needs an additional piece of information if it is to be solved numerically.
When dy/dt=1, you know that y = 8 (a.k.a. h) but you also need a specific theta or x to capture the instant in question.
Kenneth S.
ok now you know x=6, y=8 so theta is arctan (8/6)...find this on calculator using RADIAN MODE. cos of theta is 6/10 so sec of theta is 5/3. look at the equation that i obtained by implicit differentiation; you now have to figure out what is dx/dt, at the instant in question; when you have that, you will have numbers for every quantity except the one that you wish to solve for, namely deriv. w.r.t. time of theta.
Report
08/13/17
John J.
08/13/17