System of Equations

Question

Translate to a system of equation but do not solve

 

The perimeter of a standard tennis court when used for doubles play is 228 ft. The width is 46ft less than the length. Find the dimensions.

 

A. w-1 = 46

    2l +2w=228

 

B. w=1-46

    2l +2w=228

 

c. w=46 - 1

   2l+2w = 228

Answer 1

The two equations are:

2X+2y = 228

x=length and y =width

The other equation is

x-46=y

In your answers I suppose that 1 is length

2X+2y = 228 

x-46=y

The answer is B

Answer 2

Let L = the length of the tennis court

Let W = its width

 

We have two unknowns (L and W), so we need two equations to solve for the unknowns.

 

Equation 1: The perimeter of a standard tennis court when used for doubles play is 228 ft

 

The perimeter is the distance around the outside of the tennis court.  Starting from a corner, you walk one length, then turn and walk along the width, the turn and walk another length, then turn and walk another width to get back to where you started.  So you walked two lengths (2L) and two widths (2W), and that distance is 228 feet.

 

2L + 2W = 228

 

Equation 2: The width (W) is 46ft less (-46) than the length (L):  W = L - 46