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System of Equations

Translate to a system of equation but do not solve
 
The perimeter of a standard tennis court when used for doubles play is 228 ft. The width is 46ft less than the length. Find the dimensions.
 
A. w-1 = 46
    2l +2w=228
 
B. w=1-46
    2l +2w=228
 
c. w=46 - 1
   2l+2w = 228
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2 Answers

The two equations are:
2X+2y = 228
x=length and y =width
The other equation is
x-46=y
In your answers I suppose that 1 is length
2X+2y = 228 
x-46=y
The answer is B
Let L = the length of the tennis court
Let W = its width
 
We have two unknowns (L and W), so we need two equations to solve for the unknowns.
 
Equation 1: The perimeter of a standard tennis court when used for doubles play is 228 ft
 
The perimeter is the distance around the outside of the tennis court.  Starting from a corner, you walk one length, then turn and walk along the width, the turn and walk another length, then turn and walk another width to get back to where you started.  So you walked two lengths (2L) and two widths (2W), and that distance is 228 feet.
 
2L + 2W = 228
 
Equation 2: The width (W) is 46ft less (-46) than the length (L):  W = L - 46