0

# System of Equations

Translate to a system of equation but do not solve

The perimeter of a standard tennis court when used for doubles play is 228 ft. The width is 46ft less than the length. Find the dimensions.

A. w-1 = 46
2l +2w=228

B. w=1-46
2l +2w=228

c. w=46 - 1
2l+2w = 228

### 2 Answers by Expert Tutors

Francisco E. | Francisco; Civil Engineering, Math., Science, Spanish, Computers.Francisco; Civil Engineering, Math., Sci...
5.0 5.0 (1 lesson ratings) (1)
2
The two equations are:
2X+2y = 228
x=length and y =width
The other equation is
x-46=y
2X+2y = 228
x-46=y
Philip P. | Effective and Affordable Math TutorEffective and Affordable Math Tutor
5.0 5.0 (428 lesson ratings) (428)
0
Let L = the length of the tennis court
Let W = its width

We have two unknowns (L and W), so we need two equations to solve for the unknowns.

Equation 1: The perimeter of a standard tennis court when used for doubles play is 228 ft

The perimeter is the distance around the outside of the tennis court.  Starting from a corner, you walk one length, then turn and walk along the width, the turn and walk another length, then turn and walk another width to get back to where you started.  So you walked two lengths (2L) and two widths (2W), and that distance is 228 feet.

2L + 2W = 228

Equation 2: The width (W) is 46ft less (-46) than the length (L):  W = L - 46