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How to find minimum value of

5sin2x+4cos2

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Francisco E. | Francisco; Civil Engineering, Math., Science, Spanish, Computers.Francisco; Civil Engineering, Math., Sci...
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5sin2 x+4cos2 x = 
5sin2 x+ 4(1-sin2x) =
sin2x + 4 = The minimum value of this expression is 4 no matter the value of x. It occurs when x=0