Inactive Tutor answered • 07/06/14
Tutor
New to Wyzant
5sin2 x+4cos2 x =
5sin2 x+ 4(1-sin2x) =
sin2x + 4 = The minimum value of this expression is 4 no matter the value of x. It occurs when x=0
Prasenjeet S.
asked • 07/06/14How to find minimum value of
5sin2x+4cos2x
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