If 3.18 g BaCl2 is dissolved in enough solvent to make 500.0 mL of solution, what is the molarity of this solution?

Question

Please clearly include step by step how to solve the equation including any conversions you may have to do and the formula.

Answer 1

Molar mass BaCl2 = 208.2 g/mole

3.18 g x 1 mole/208.2 g = 0.0153 moles

0.0153 moles/0.500 L = 0.0305 mol/L = 0.0305 M (to 3 significant figures)