Need help with a question using the quadratic formula

Question

Could someone help me with this question step-by-step using the quadratic formula?

 

3x²-17x+10

Answer 1

the quadratic formula is...

(-b±√[b²-4ac])/2a for use with a trinomial in the form ax²+bx+c

3x²-17x+10 where a=3, b=-17 and c=10

(17±√[289-120])/6

(17±√169)/6

(17±13)/6

30/6 and 4/6

5 and 2/3

(x-5)(3x-2)

 

you could also factor...

3x^2-17x+10

3*10=3*2*5=2*(3*5)=2*15 and 2+15=17, the coefficient of the middle term

(3x-2)(x-5)