
Arturo O. answered 07/17/17
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There are 2 limits, when x→2- and when x→2+. In the neighborhood of x = 2, you are in the region where
f(x) = x2 + 3x + 1
So whether you approach 2 from the left or the right, the limit approaches 22 + 3(2) + 1 = 11
limx→2+ f(x) = 11
limx→2- f(x) = 11
Since the 2 limits are equal, the limit at x = 2 is defined, and equal to 11.
Don J.
07/17/17