
Suneil P. answered 06/30/14
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Assuming your question is simplify (t3-t)/(t3-t2), we can first factor t from the numerator and t2 from the denominator. We basically factor the lowest degree term from each expression (since the lowest deg term is common in every term of the expression).
We hence have t(t2-1)/(t2(t-1))=(t2-1)/(t(t-1)) obtained through dividing numerator and denominator by t (assuming t non-zero).
Then, we can once again factor...the denominator is already factored (being a product of linear terms); the numerator can be factored into (t-1)(t+1) via difference of squares.
Assuming t is not equal to 1 (else we would be dividing by 0), we can now divide both num and denom by t-1, obtaining (t+1)/t.
At this point we could distribute the 1/t to obtain 1+1/t, which concurs with your answer.
Hope this helps :)


Suneil P.
Sorry, 1+1/t ?
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06/30/14

Suneil P.
Note that you can check that 1+1/t is the correct ans as you can "cross-multiply"...it's like checking that 4*3=12, given that you had to solve 12/3
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06/30/14
Jacqueline F.
I cross checked the math and I came up with the same answer as Suneil P., that is, 1 + 1/t.
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06/30/14
Suneil P.
06/30/14