Michael C. answered 07/12/17
Tutor
4.9
(10)
PhD with 20 years experience teaching math and applied science
Let the number of dimes be d, and the number of nickels be n
n = d + 5; or n - d = 5 (1) (amount of coins)
5n + 10d = 550 or n + 2d = 110 (2) (amount of money all together)
substituting n from (1) into (2); d + 5 + 2d = 110
3d = 105; or d = 105/3 = 35
from (1) n = 35 + 5 = 40
checking; 35 * 0.1 + 40 * 0.05 = 3.50 + 2.00 = 5.50