
Arturo O. answered 07/10/17
Tutor
5.0
(66)
Experienced Physics Teacher for Physics Tutoring
Work this by setting the energies at the 2 points equal to each other, and solve for the speed. The answer will not depend on the mass.
(1/2)mv12 + mgh1 = (1/2)mv22 + mgh2
(1/2)v12 + gh1 = (1/2)v22 + gh2
v2 = √[v12 + 2g(h1 - h2)] = √[(10)2 + 2(9.8)(20 - 10)] ≅ 17.2 m/s