
Andrew M. answered 07/08/17
Tutor
New to Wyzant
Mathematics - Algebra a Specialty / F.I.T. Grad - B.S. w/Honors
Imagine 16 numbers in the set and, when
put in order from least to greatest, the
8th number is 57 and the 9th number
is 59. The median would be the mean,
or average of 57 and 59...
(57+59)/2 = 58
Then there would be 8 numbers less
than 58 and 8 numbers greater than
58 with a total of 16 numbers.
Thus works for any set of 16 numbers
where the average of the 8th and 9th
terms is 58.