Patrick L. answered • 07/05/17
Tutor
4.8
(58)
AA in Mathematics with 5+ Years of Tutoring Experience
You are given a point (-10, -1) and the equation y = (3/5)x - 11.
1. Find the negative reciprocal of the slope and use the point-slope form.
m = (-5/3)x and y - (-1) = -5/3(x - (-10)) ⇒ y + 1 = -5/3(x + 10)
2. Distribute -5/3 and then subtract 1 on both sides. Note: change from 1 to 3/3 due to least common denominator.
y + 1 = (-5/3)x - 50/3 ⇒ y + 3/3 = (-5/3)x - 50/3 ⇒ y = (-5/3)x - 53/3
Andrew M.
Good question. The student posted an equation of a line and a point but did not state what he needed to determine. Are we looking for the perpendicular line, the parallel line, or maybe just trying to see if the point (-10, -1) is on the line ....
Please tell us what you need to find.
Report
07/06/17
Melisa B.
Write an equation in slope intercept form of the line that passes through the given point and is parallel to the graph of the given equation.
(-10,3)y=5x-7
Report
07/06/17
Melisa B.
Write an equation in slope intercept form of the line that passes through the given point and is parallel to the graph of the given equation.
(-10,-1);y=3/5x-11
Report
07/06/17
Patrick L.
tutor
1. For the line to be parallel, the slope will be the same with a different y-intercept.
y = 5x - 7 with point (-10, 3)
The slope will be 5. So by using the point-slope form, y - 3 = 5(x - (-10)).
y - 3 = 5(x + 10)
y - 3 = 5x + 50
y = 5x + 53
2. y = 3/5x - 11 with point (-10, -1)
The slope will be 3/5. So by using the point-slope form, y - (-1) = 3/5(x - (-10)).
y + 1 = 3/5(x + 10)
y + 1 = 3/5x + 30/5
y + 1 = 3/5x + 6
y = 3/5x + 5
Report
07/06/17
Mark M.
07/05/17