
Arturo O. answered 07/03/17
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If the 2 machines are working in parallel, the reciprocals of the individual times add up to the reciprocal of the net time, making the net time smaller than ether individual time.
T1 = time it takes 2010 machine to FAX = 9 min
T2 = time it takes 2014 machine to FAX = 8 min
T = time it takes to FAX when they work together
1/T = 1/T1 + 1/T2
T = T1T2 / (T1 + T2) = [(9)(8) / (9 + 8)] min ≅ 4.235 min