The height of the ball (in feet) written in terms of the time (in seconds) is modled by f(t)=-16t+32t+48t. What is the height of the ball?

Question

What is the height ?

Answer 1

The equation is incorrect.  The first term should be -16t², which corresponds to -(1/2)gt², where g = 32 ft/s².  Also, there should be a constant term corresponding to initial height.  I suspect you have a few typos in the problem statement.  It is probably

 

f(t) = -16t² + 32t + 48,

 

with t in seconds and height f in feet.  In any case, to find the height at a particular time t (with t=0 set at the moment the ball is tossed), plug t in seconds into f(t) and get height f.