help me please

Question

Juan needs to mix a 20% alcohol solution with a 60% alcohol solution to create 200 millileters of a 48% solution. How many millileters of each solution must Juan use?

A) Write an equation using the information as it is given above that can be used to solve this problem. Use x as your variable to represent the quantity of 20% alcohol solution.
Equation:

Answer 1

If x is the volume of the 20% alcohol solution, then you will have 200-x of the 60% alcohol solution.

Use the decimal version of each percentage in your equation: 48%=0.48; 20%=0.20; 60%=0.60

Set up an equation with one side as your final solution, and the other what you will be mixing. The end solution has 200 mL and a concentration of 48%:

(200)(0.48) = (x)(0.20) + (200-x)(0.60)                      simplify and distribute
96 = 0.20x + 120 - 0.60x                                           combine like terms
-24 = -0.40x                                                             divide both sides by -0.40 to get x
60 = x

So we will have 60 mL of the 20% solution, and 140 of the 60% solution.

Answer 2

Juan needs to mix a 20% alcohol solution with a 60% alcohol solution to create 200 millileters of a 48% solution. How many millileters of each solution must Juan use?

A) Write an equation using the information as it is given above that can be used to solve this problem. Use x as your variable to represent the quantity of 20% alcohol solution.
Equation:

Let x = amount (ml) of 20% solution

then

200-x = amount (ml) of 60% solution

.20x + .60(200-x) = .48(200)