how many grams of Liquid sulfuric acid would react completely with 4.56 grams of aqueous ammonium hydroxide?

Question

Stoichiometry mass to mass problem. How many grams of Liquid sulfuric acid would react completely with 4.56 grams of aqueous ammonium hydroxide?

Answer 1

 

The balanced equation is:

2NH4OH + H2SO4 ==> (NH4)2SO4 + 2H2O

4.56 g NH4OH x 1 mole/35 g = 0.130 moles

moles H2SO4 needed = 0.130 moles NH4OH x 1 mole H2SO4/2 moles NH4OH = 0.0651 moles H2SO4

0.0651 moles H2SO4 x 98.1 g/mole = 6.38 grams of H2SO4 required