let f(x)=(3x)/(x-q) ...

Question

q cannot be equal to x.

 

a) find the equations of the vertical and horizontal asymptotes of the graph of f.

 

the vertical and horizontal asymptotes to the graph of f intersect at the point Q(1,3)

 

b) find the value of q

 

c) the point P(x,y) lies on the graph of f. show that PQ = sqrt( ((x-1)^2) + ( (3)/(x-1) )^2 )

 

d) Find the coordinates of the points on the graph of f that are closest to (1,3)

Answer 1

a)  The vertical asymptote is the value of x such that x-q = 0(i.e. when the f(x)-> ∞.

     Therefore, x = q.

 

     The horizontal asymptote is the value of f(x) when x-> ∞.

      Therefore, y = 3 (the ratio of the coefficients of x in f(x))

 

b)  Since the these two lines intersect at Q(1, 3), the value of q = 1.  (the value of x is the vertical asymptote and the value of y is the horizontal asymptote.

 

c)  PQ = √((x-1)² + (f(x)-3)).     Replace f(x) by (3x)/(x-1) and simplify.

 

d)  Minimize  (x-1)² + ((3x)/(x-1) - 3)).

 

I hope this helps.