
Francisco E. answered 05/26/14
Tutor
5
(1)
Francisco; Civil Engineering, Math., Science, Spanish, Computers.
If Bus B and Bus C leave Eastport at the same time and bus C is faster than bus B, is obvious that C will pass bus A first. The equation will be 40(t-7) = 60(t-7.75) 45 min are 0.75 of an hour. Solving this equation for t, we obtain t= 9.25 = 9:15 => we may conclude that after (9.25 - 7.75) = 1.5 hours of leaving Bus B will pass bus A. After bus C running for 90 kilometers this will happen. To test, bus 1 will have run (9.25-7)= 2.25 hours and the distance is 90 kilometers.
Problem 1 is similar and the equation is
(t-0)*560 = t(-45)*750, solve for t and get the time when this happens.


Francisco E.
I agree, although I think that the person who writes to this section is looking for an answer of a problem and a methodology of solving it, so he or she will apply the same in other cases. I believe that in five to ten minutes is pretty difficult to cover
theoretical basis and also practice the problems, they are at School and the teacher will try to explain the subject. If I am his tutor is another thing. Here I am trying to help them in solving some "difficult" problems.
Thanks for exposing your point of view and also have a very nice Memorial Day.
Report
05/26/14
Andrew L.
05/26/14