factor the expression

-216x

^{3}+1 = (-6x)^{3}+1This is a "sum of cubes" (since 1 = 1

^{3}), which has the form:a

^{3}+ b^{3}= (a + b)(a^{2}- ab + b^{2})In this problem, a = -6x and b = 1

**-216x**

^{3}+ 1 = (-6x + 1)(36x^{2}+ 6x + 1)
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