Arthur D. answered 05/03/14
Tutor
4.9
(274)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
let x=# of Chen's items
let x-1=# of Jo's items
ley y=# of pounds each of Chen's items weigh
let y+0.5=# of pounds each of Jo's items weigh
each bag weighs 15 pounds
xy=15
(x-1)(y+0.5)=15
from xy=15 we have y=15/x
substituting we get...
(x-1)[(15/x)+0.5]=15
multiply both sides by x
(x-1)(15+0.5x)=15x
15x-15+0.5x^2-0.5x=15x
subtract 15x from both sides
-15+0.5x^2-0.5x=0
multiply both sides by 2
-30+x^2-x=0
x^2-x-30=0
factor
(x-6)(x+5)=0
x-6=0
x=6
Chen has 6 items weighing 15 pounds
Jo has 6-1=5 items weighing 15 pounds
check:15/6=2.5 pounds for each of Chen's items
15/5=3 pounds for each of Jo's items
3 is 0.5 pounds more than 2.5 pounds